SOLUTION: #1. A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation h = -16 t^2 + 96 t + 122 models the b

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Question 831087: #1.
A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the ball's height h above the ground in feet, t seconds after it was thrown.
How high is the ball after 3 seconds?


How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
#1.
A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the ball's height h above the ground in feet, t seconds after it was thrown.
How high is the ball after 3 seconds?
set t=3 and solve:
h = -16*3^2 + 96*3 + 122
h = -16*9 + 96*3 + 122
h = -144 + 288 + 122
h = 144 + 122
h = 266 feet
How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.
set h=0 and solve for t:
0 = -16t^2 + 96 t + 122
solve using the quadratic formula to get:
t={-1.1, 7.1}
throw out the negative solution (extraneous) leaving:
t = 7.1 seconds
.
Details of quadratic formula:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=17024 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -1.07737660757502, 7.07737660757502. Here's your graph:

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