SOLUTION: A passenger train leaves Chicago for Birmingham one hour later than a freight train leaves Birmingham for Chicago. The trains are 583 miles apart on parallel tracks. The passenger
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Question 829821: A passenger train leaves Chicago for Birmingham one hour later than a freight train leaves Birmingham for Chicago. The trains are 583 miles apart on parallel tracks. The passenger train travels at 120 miles per hour, and the freight train travels at 75 mph. Where do they meet?
Found 2 solutions by TimothyLamb, lwsshak3:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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s = d/t
t = d/s
d = s*t
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freight train head-start:
d = 75 mi/hr * 1 hr
d = 75 miles
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relative distance between the trains, when the passenger train departs Chicago:
583 - 75 = 508 miles
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relative speed of the two trains:
120 + 75 = 195 mph
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elapsed time since the passenger train departs Chicago, when the merge occurs:
t = d/s
t = 508/195
t = 2.605128205128205 hours
---
the meet (relative to the passenger train's departure point):
d = s*t
d = 120 mi/hr * 2.605128205128205 hours
d = 312.6 miles from Chicago
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Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A passenger train leaves Chicago for Birmingham one hour later than a freight train leaves Birmingham for Chicago. The trains are 583 miles apart on parallel tracks. The passenger train travels at 120 miles per hour, and the freight train travels at 75 mph. Where do they meet?
***
let x=distance passenger train traveled
583-x=distance freight train traveled
travel time=distance/speed
freight train traveled one hour longer than freight train.
..
120(583-x)-75x=75(120)
69960-120x-75x=9000
195x=60960
x=312.62
583-x=270.38
Trains meet after passenger train has traveled 312.62 miles and freight train has traveled 270.38 miles
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