SOLUTION: [ A rock is thrown upward from the edge of a cliff. The rock follows the equation below. h(t)= -16t^2+64t+63 ]

Question 825117: [ A rock is thrown upward from the edge of a cliff. The rock follows the equation below. h(t)= -16t^2+64t+63 ]
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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h(t) = -16t^2 + 64t + 63
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the above quadratic equation is in standard form, with a=-16, b=64, and c=63
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-16 64 63
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the t-intercepts), which are:
t = -0.817356917
t = 4.81735692
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the negative root does not fit the problem statement, so use the positive root
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judging from the value of the gravitational acceleration constant:
the time units are seconds, and the height units are feet
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answer:
at t = 4.81735692 seconds after being thrown, the rock hits the ground
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the quadratic vertex is a maximum at: ( t= 2, h= 127 )
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at t = 2 seconds the rock reaches its maximum height of 127 feet
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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