SOLUTION: leroy started his car at the rate of 50km/hr. one hour later, tina left from the same point driving along the same road at 75 km/h how long did it take her to catch up with leroy?

Question 82311: leroy started his car at the rate of 50km/hr. one hour later, tina left from the same point driving along the same road at 75 km/h how long did it take her to catch up with leroy?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
leroy started his car at the rate of 50km/hr. one hour later, tina left from the same point driving along the same road at 75 km/h how long did it take her to catch up with leroy?
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Leroy DATA:
Rate = 50 km/hr ; Time = x hrs. ; Distance = rt = 50x km
---------------
Tina DATA:
Rate = 75 km/hr ; Time = (x-1) hrs. ; Distance = 75(x-1) = 75x-75 km
-----------------
EQUATION:
distance = distance
50x = 75x-75
-25x=-75
x=3 hrs (Leroy's time)
x-1 = 2 hrs (Tina's time)
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Cheers,
Stan H.
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