SOLUTION: Walking at 4.5 km. in 1 hour a clerk reaches his office 5 minutes late. If he walks 3.5 km. in 40 minutes, he would reach the office 4 minutes early. The distance of the office is-

Question 822594: Walking at 4.5 km. in 1 hour a clerk reaches his office 5 minutes late. If he walks 3.5 km. in 40 minutes, he would reach the office 4 minutes early. The distance of the office is-
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Walking at 4.5 km. in 1 hour a clerk reaches his office 5 minutes late. If he walks 3.5 km. in 40 minutes, he would reach the office 4 minutes early. The distance of the office is-
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Fast Walk DATA:
rate = 4.5 km/hr ; time = [(x+5)/60] hrs ; distance = 4.5[(x+5)/60] km
-----------------
Slow Walk DATA:
rate = 3.5/(2/3) = 10.5/2 = 5.25 km/hr ; time = (x-4)/60 hrs ;
distance = 5.25[(x-4)/60] km
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Equation:
distance = distance
4.5[(x+5)/60] = 5.25[(x-4)/60]
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4.5x + 22.5 = 5.25x-21
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0.75x = 43.5
x = 58 minutes
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Ans: Distance = 4.5(58+5)/60 = 4.725 km
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Cheers,
Stan H.
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