SOLUTION: [ [Genny] & Jill left home at the same time. They traveled in opposite directions. Jill traveled 15 mph faster than [Genny]. After 6 hrs. they were 630 km apart. Find [Genny's] spe

Question 816553: [ [Genny] & Jill left home at the same time. They traveled in opposite directions. Jill traveled 15 mph faster than [Genny]. After 6 hrs. they were 630 km apart. Find [Genny's] speed. ]
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
g = genny's speed
j = jill's speed
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j = g + 15
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since they travel in exactly opposite directions, the vector math for their relative speed is trivial, and we can simplify by assuming a single traveler moving at the relative speed of the two travelers.
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relative speed:
s = g + (g + 15)
s = 2g + 15
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s = d / t
s = 630/6
2g + 15 = 630/6
2g + 15 = 105
2g = 105 - 15
2g = 90
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g = 45 mph
j = 60 mph
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