SOLUTION: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
Can u pls draw a table how u worked it out and also a
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
Can u pls draw a table how u worked it out and also a
Log On
Question 810632: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
Can u pls draw a table how u worked it out and also a diagram pls thank you Found 2 solutions by TimothyLamb, stanbon:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! (48 + 52)/2 = 50
s = d / t
d = s * t
---
d = 50 * 5 = 250 miles
---
because d is the round-trip distance, the car can drive a maximum of 125 miles before it must return, if it wants to make the round trip in 5 hours.
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php
You can put this solution on YOUR website! In 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
-------
Going DATA:
time = x hrs ; rate = 48 mph ; distance = 48x miles
-------
Returning DATA:
time = 5-x hrs ; rate = 52 mph ; distance = 52(5-x) = 260-52x miles
----------
Equation:
distance going = distance returning
48x = 260-52x
100x = 260
x = 2.6 hrs
-----
Total distance = 48x+(260-52x) = 260-4x = 260-4*2.6 = 249.6 miles
-----
Cheers,
Stan H.
=============
(