SOLUTION: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
Can u pls draw a table how u worked it out and also a
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Question 810632: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
Can u pls draw a table how u worked it out and also a diagram pls thank you
Found 2 solutions by TimothyLamb, stanbon:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
(48 + 52)/2 = 50
s = d / t
d = s * t
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d = 50 * 5 = 250 miles
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because d is the round-trip distance, the car can drive a maximum of 125 miles before it must return, if it wants to make the round trip in 5 hours.
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
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Going DATA:
time = x hrs ; rate = 48 mph ; distance = 48x miles
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Returning DATA:
time = 5-x hrs ; rate = 52 mph ; distance = 52(5-x) = 260-52x miles
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Equation:
distance going = distance returning
48x = 260-52x
100x = 260
x = 2.6 hrs
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Total distance = 48x+(260-52x) = 260-4x = 260-4*2.6 = 249.6 miles
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Cheers,
Stan H.
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