SOLUTION: Car travels 200 miles. A second car, making the same trip, travels 10 mph faster than the first car and makes the trip in 1 hour less. Find the speed of each car. ?? Email: b

Question 806037: Car travels 200 miles. A second car, making the same trip, travels 10 mph faster than the first car and makes the trip in 1 hour less. Find the speed of each car. ??
Email: bbminc@aol.com
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
First car ------------ speed ---------------x mph-----------200 miles
time first car = 200/x

Second car-----------speed ---------------(x+10) mph----------200 miles
time second car = 200/(x+10)
Time first car - time second car = 1

LCD = x(x+10)
200(x+10)-200x=1*x(x+10)
200x+2000-200x=x^2+10x
x^2+10x-2000=0
x^2+50x-40x-2000=0
x(x+50)-40(x+50)=0
(x+50)(x-40)=0
x= 40 OR -50
ignore negative
x= 40 speed of first car
speed of second car = 40+10 = 50 mph

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