SOLUTION: Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same time. The first group is headed up at a speed of 63 me

Algebra.Com
Question 805396: Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same time. The first group is headed up at a speed of 63 meters per minute. The second is headed down at a speed of 260 meters per minute. How long will it be before the elevators are 270 meters apart?
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
63t+260t=270
t = 0.83591 minutes
t= 50.155 seconds

RELATED QUESTIONS

Jose is on an elevator on the top floor of a building. Ellie is on the bottom floor... (answered by ankor@dixie-net.com)
In a tall office building, one elevator leaves the third floor and ascends at a speed of... (answered by stanbon)
two groups are visiting a museum the first group includes four adults and 20 students... (answered by josgarithmetic)
Two tourists who are at a distance of 40 km from their camp must reach it together in the (answered by ikleyn)
Aaron, Chris, Maria, Sonia, and Ling are on a class committee. They want to choose two... (answered by stanbon)
A survey of 1,092 tourists visiting Orlando was taken. Of those surveyed: 287 tourists (answered by Boreal)
A survey of 1,003 tourists visiting Orlando was taken. Of those surveyed: 281 tourists (answered by ikleyn)
A survey of 1,174 tourists visiting Orlando was taken. Of those surveyed: 250 tourists (answered by mccravyedwin,ikleyn,Edwin McCravy)
A survey of 1,062 tourists visiting Orlando was taken. Of those surveyed: 273 tourists (answered by ikleyn)