SOLUTION: The distance between two stations A and B is 300 km. Two motor cyclists start simultaneously from A and B in the opposite directions and the distance between them after three hours
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Question 803188: The distance between two stations A and B is 300 km. Two motor cyclists start simultaneously from A and B in the opposite directions and the distance between them after three hours is 30 km. If the speed of one motor cyclist is less than that of the other by 10 km\hr, find the speed of each motor cyclist.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
In there hours they both have traveled 270 km. (300-30)
speed of one be x
the speed of other = x-10
they are moving towards each other
so combined speed = x+x-10
=2x-10 km/h
t=d/r
3= 270/(2x-10)
2x-10 = 270/3
2x-10 = 90
2x=90+10
2x=100
x= 50
speed of one is 50 km/h
the speed of other = 50-10 = 40 km/h
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