SOLUTION: Two planes travel are heading toward each other from two cities that are 1615 miles apart. Slow plane is traveling 80 km/h more that half the rate of the fast plane. Both planes m

Question 802571: Two planes travel are heading toward each other from two cities that are 1615 miles apart. Slow plane is traveling 80 km/h more that half the rate of the fast plane. Both planes meet after traveling 3 hours and 48 minutes. What are the rate of speed for each plane?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Faster plane = x
slower plane = (x/2)+80
They are moving towards each other
add up speeds
x+(x/2)+80
3x/2 +80
distance = 1615
time = 3 hours 48 minutes
=3.8 hoursOR 19/5
t=d/r
= 1615/((3x/2)+80)
19/5 = 1615/((3x/2)+80)
((3x/2)+80)=5*1615/19
3x/2 + 80 = 85*5
3x/2 +80 = 425
3x/2 = 425-80
3x/2 = 345
3x=2*345
3x=690
x=230
Faster plane speed = 230 mph
slower plane speed = 3x/2 +80
=230/2 +80
=115+80
=195 mph
=
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