SOLUTION: Jamie recently drove to visit her parents who live 390 miles away. On her way there her average speed was 11 miles per hour faster than on her way home (she ran into some bad weath
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Question 802147: Jamie recently drove to visit her parents who live 390 miles away. On her way there her average speed was 11 miles per hour faster than on her way home (she ran into some bad weather). If Jamie spent a total of 13 hours driving, find the two rates.
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Jamie recently drove to visit her parents who live 390 miles away. On her way there her average speed was 11 miles per hour faster than on her way home (she ran into some bad weather). If Jamie spent a total of 13 hours driving, find the two rates.
distance = 390 miles
on her way there speed = x mph
time taken = 930/x
On her return speed was x-11 mph
time = 930/(x-11)
Time to go there + time to return = 13 hours
930/x +930/(x-11) = 13
Multiply by x(x-11)
930(x-11)+930x=13x(x-11)
930x-10230+930x=13x^2-143x
Re arrange
13x^2-1860x-143x+10230=0
13x^2-2003x+10230=0
Find the roots of the equation by quadratic formula
a= 13 b= -2003 c= 10230 2916
b^2-4ac= 4012009 - 531960
b^2-4ac= 3480049 = 1865.49
)/
x1=( 2003 + 1865.49 )/ 26
x1= 148.79
x2=( 2003 - 1865.49 )/ 26
x2= 5.29
Ignore 5.29
x = 148.79 mph to go there
Return will be 11 mph less
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Jamie recently drove to visit her parents who live 390 miles away. On her way there her average speed was 11 miles per hour faster than on her way home (she ran into some bad weather). If Jamie spent a total of 13 hours driving, find the two rates.
Using S as the average speed on the return trip leads to the quadratic equation: , which when factored results in S, or average speed on return trip being: mph, and average speed on trip to house being 55 + 11, or mph
You can do the check!!
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