SOLUTION: Suppose Liz drove 100 miles then increased her speed by 30mph for the following 200 miles. If the second part took 1 hour less than the first part, what was the average speed in th

SOLUTION: Suppose Liz drove 100 miles then increased her speed by 30mph for the following 200 miles. If the second part took 1 hour less than the first part, what was the average speed in th

Algebra.Com

Question 800294: Suppose Liz drove 100 miles then increased her speed by 30mph for the following 200 miles. If the second part took 1 hour less than the first part, what was the average speed in the first part?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
r*t=100,
(r+30)*(t-1)=200
r = 20, t = 5
check
5*20=100
50*4=200
ok

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