SOLUTION: Two cyclists leave a city at the same time, one going east the other going west. The west bound cyclist bikes 4 mph faster than the east bound cyclist. After 5 hours they are 200 m

Question 799370: Two cyclists leave a city at the same time, one going east the other going west. The west bound cyclist bikes 4 mph faster than the east bound cyclist. After 5 hours they are 200 miles apart. How fast is the east bound cyclist riding?
Found 2 solutions by solver91311, Finavon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

The sum of their speeds had to be 200 divided by 5, so:

Solve for

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by Finavon(81) (Show Source): You can put this solution on YOUR website!
speeds e and w
w=e+4
in one hour they will be 200/5 miles apart
w+e=40
substitute for w
e+4+e=40
2e=36
e=18
w=18+4=22
East at 18 mph; West at 22 mph

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