SOLUTION: teri begins walking east at 2mph at 1:00. Cindy leaves from the same point 30 min. later going east at 3mph. when will she catch teri? tamerson@cornerstonechristain.net

Question 795635: teri begins walking east at 2mph at 1:00. Cindy leaves from the same point 30 min. later going east at 3mph. when will she catch teri?
tamerson@cornerstonechristain.net
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
teri begins walking east at 2mph at 1:00.
Cindy leaves from the same point 30 min. later going east at 3mph.
when will she catch teri?
:
since we are using mph, change 30 min to .5 hrs
:
Let t = time for C to catch T
then
(t+.5) = the travel time of T
:
When C catches T, they will have traveled the same distance
Write a distance equation; dist = speed * time
:
3t = 2(t + .5)
3t = 2t + 1
3t - 2t = 1
t = 1 hr for C to catch T
:
:
Check this by finding the actual distance of each, should be equal
3(1) = 3 mi
2(1.5) = 3 mi
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