SOLUTION: d..ch5 #19 A plane took 1 hour longer to travel 560miles on the first portion of a flight than it took to fly 480miles on the second portion. If the speed was the same for each

Click here to see ALL problems on Travel Word Problems

Question 78860: d..ch5
#19
A plane took 1 hour longer to travel 560miles on the first portion of a flight than it took to fly 480miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?

Found 5 solutions by ankor@dixie-net.com, muthbab@gmail.com, greenestamps, josgarithmetic, MathTherapy:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?
:
Let t = time of the 2nd portion (480 mi)
Then (t+1) = time of the 560 mi portion:
;
The speed is the same on both portions, write an equation from this fact:
s = distance/time
:
560 mi speed = 480 mi speed
=
:
Cross multiply and you have:
560t = 480(t+1)
560t = 480t + 480
560t - 480t = 480
80t = 480
t = 480/80
t = 6 hrs
:
:
Check solution by finding the speed, which should be the same:
560/7 = 80
480/6 = 80

Answer by muthbab@gmail.com(5)   (Show Source):
You can put this solution on YOUR website!
560/t = 480/(t-1); Solving for t-----> t=7. Therefore the second part of the flight took 6hours.

Answer by greenestamps(13367)   (Show Source):
You can put this solution on YOUR website!

In the extra hour, the plane flew an additional 80 miles.
That means the speed of the plane was 80mph.
That means the time required to fly the 480 miles of the second portion of the flight was 6 hours.

ANSWER: 6 hours

Answer by josgarithmetic(39838)   (Show Source):
You can put this solution on YOUR website!

SPEED TIME DISTANCE firstportion r 560/r 560 secondportion r 480/r 480 difference 1

-------solve for r, and evaluate .

-
secondportion time, 6 hours

Answer by MathTherapy(10858)   (Show Source):
You can put this solution on YOUR website!

d..ch5
#19
A plane took 1 hour longer to travel 560miles on the first portion of a flight than it took to fly 480miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?

Let the time taken to complete the second leg, be T
Then the time taken to complete the first leg = T - 1
We then get the following SPEED equation:
----- Factoring out GCF, 80, in numerator
7T = 6(T + 1) ------ Cross-multiplying
7T = 6T + 6
7T - 6T = 6
Time taken to complete second leg, or