Question 783314: Two cyclists race one against the other on a 500 m circular track, leaving together from the starting line and each one doing 10 laps. Knowing that the first cyclist travels at a speed of 55km/h and the second one travels at a speed of 20km/h, when will the first cyclist overtake the second by four laps?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! wo cyclists race one against the other on a 500 m circular track, leaving together from the starting line and each one doing 10 laps.
Knowing that the first cyclist travels at a speed of 55km/h and the second one travels at a speed of 20km/h, when will the first cyclist overtake the second by four laps?
:
These are some fast runners||
:
4 laps is a total of 4(500) = 2000 m; change this to 2 km (speed in km/hr)
:
When will the two runners be 2 km apart?
Let t = elapsed time for this to be true.
:
Write a dist equation; dist = speed * time
:
Fast runner d - slow runner d = 2
55t - 20t = 2
35t = 2
t = 2/35
t = .057 hrs, .057(60) = 3.43 minutes
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
Response
I assumed when they used the word "when" it meant how long it took the faster
runner to be 4 laps ahead of slow runner, 4 laps being 2 km
|
|
|
