SOLUTION: Suppose two trains leave the station at the same time, traveling in opposite directions. One train travels 10 mph faster than the other. In 3.5 hours, the trains are 322 miles apar

Question 780360: Suppose two trains leave the station at the same time, traveling in opposite directions. One train travels 10 mph faster than the other. In 3.5 hours, the trains are 322 miles apart. Find the speed of each train. Help! Not sure when to use the d=r*t formula or the t=d/r = aaarrrgghhh!!!!!
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Suppose two trains leave the station at the same time, traveling in opposite directions. One train travels 10 mph faster than the other. In 3.5 hours, the trains are 322 miles apart. Find the speed of each train. Help! Not sure when to use the d=r*t formula or the t=d/r = aaarrrgghhh!!!!!

Let slower train's speed be S

Then faster train's speed = S + 10

Create a DISTANCE EQUATION that equates to:
Distance traveled by slower train, in 3.5 hours, plus distance traveled by faster train, in 3.5 hours, equals total distance between them. In algebraic terms, this is translated as:

3.5S + 3.5(S + 10) = 322

3.5S + 3.5S + 35 = 322

7S = 322 - 35

7S = 287

S, or speed of slower train = , or mph

Speed of faster train = 41 + 10, or mph

You can do the check!!

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