SOLUTION: A cyclist leaves his training base for a morning workout, riding at the rate of 10 mph. One and one-half hours later, his support staff leaves the base in a car going 25 mph in the

Question 779915: A cyclist leaves his training base for a morning workout, riding at the rate of 10 mph. One and one-half hours later, his support staff leaves the base in a car going 25 mph in the same direction. How long will it take the support staff to catch up with the cyclist?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A cyclist leaves his training base for a morning workout, riding at the rate of 10 mph. One and one-half hours later, his support staff leaves the base in a car going 25 mph in the same direction. How long will it take the support staff to catch up with the cyclist?
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Cyslist DATA:
rate = 10 mph ; time = x hrs ; distance = r*t = 10x miles
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Staff DATA:
rate = 25 mph ; time = x - (3/2) hrs ; distance = 25(x-(3/2)) miles
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Equation:
10x = 25x - 25(3/2)
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-15x = (-75/2)
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x = 5/2 hrs
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Staff time = x-(3/2) = (5/2)-(3/2) = 1 hr. (time for the staff
to overtake the cyclist.
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Cheers,
Stan H.
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