SOLUTION: The perimeter of a rectangle is 260 meters. The length is 30 meters greater than its width. Find the dimensions of the rectangle.

Question 7757: The perimeter of a rectangle is 260 meters. The length is 30 meters greater than its width. Find the dimensions of the rectangle.
Found 2 solutions by bonster, nguy0279:
Answer by bonster(299) (Show Source): You can put this solution on YOUR website!
P=260
Length=30 greater than width...so set the width as X, and set the lenth as (X+30)

P=2L+2W
260=2(x+30)+2(X)
260=2x+60+2x <--subtract 60 from both sides
(260)-60=(2x+60+2x)-60
260=4x <--divide both sides by 4
=
65=x

since the width=x, it is 65 meters long
the length=x+30 or (65+30=95), it is 95

Answer by nguy0279(1) (Show Source): You can put this solution on YOUR website!
w=50
l=80
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