SOLUTION: If a boy walks from his house to school at 4 km/h, he reaches the school 10 minutes earlier than the scheduled time. However if he walks the rate of 3 km/h he reaches 10 minutes la
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Question 775609: If a boy walks from his house to school at 4 km/h, he reaches the school 10 minutes earlier than the scheduled time. However if he walks the rate of 3 km/h he reaches 10 minutes late. The distance of the school from his house is
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
The required time to make his trip is x, in hours. When he is early using 4 km/hour, time is x-1/6. When he is late at 3 km/hour time is x+1/6. Whether early or late, the trip is the same distance.
Traveling to school, rate*time=distance
10 minutes = 1/6 hour
Early:
Late:
Equal Distance:
hours
hour
1 hour 10 minutes if he were to be "on-time".
HOW FAR FROM HOME TO SCHOOL?
Pick either early or late expression and compute the value.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the time in hours for his trip
if he is to arrive at the scheduled time
Let = distance from school to house in km
--------------
Equation for leaving early:
---------------------
Equation for leaving late:
---------------------
By substitution:
Multiply both sides by
-----------
By substitution:
km
The distance of the school from his house is 4 km
------------
check:
km
OK
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