SOLUTION: A 100 metres long train is moving at 50 km/hr. An another train is 120 metres long is moving in opposite direction and crosses each other in 6 seconds. Find the speed of the second

Algebra.Com
Question 775332: A 100 metres long train is moving at 50 km/hr. An another train is 120 metres long is moving in opposite direction and crosses each other in 6 seconds. Find the speed of the second train?
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
A 100 metres long train is moving at 50 km/hr. An another train is 120 metres long is moving in opposite direction and crosses each other in 6 seconds. Find the speed of the second train?
The sum of lengths of the trains is the distance the second train travels.
100+120m =220m=0.22km
Let speed of second train be x km/h
They are in opposite directions.
effective speed = x+50 km/h
Time = 6 seconds = 6/3600 seconds => 1/600 hours
d=rt
0.22=(x+50)*1/600
multiply by 600
0.22*600 =x+50
132=x+50
x=132-50
x=82 km/h

RELATED QUESTIONS

How much time does a train 50m long moving at 65 km/hr take to pass another train 75 m... (answered by lwsshak3)
A passenger train travelling at 25km/hr is moving in the same direction as the truck (answered by mananth,josgarithmetic)
a train travelling 110m long is travelling at 60 km/hr in what time it will cross a... (answered by ankor@dixie-net.com)
A train T1 moving at an average speed of 90 km/h takes 8 seconds to completely cross a... (answered by ankor@dixie-net.com)
A train moving 50 miles per hour meets and passes a train moving 50 miles per hour in... (answered by toidayma)
A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite... (answered by stanbon)
how long will a boy sitting near the window of a train travelling at54 km/hr see atrain... (answered by lwsshak3)
A train moving at 49 mph meets and is passed by a train moving at 63 mph. A passenger in... (answered by ankor@dixie-net.com)
A train is moving along a straight stretch of track parallel to a highway. An automobile (answered by Theo)