SOLUTION: Monday Roger goes to work, it takes him 35 minutes . Tuesday he goes to work and he goes 9 mph more than he did monday and it took him 7 minutes less. how far does he travel to wor
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Question 770399: Monday Roger goes to work, it takes him 35 minutes . Tuesday he goes to work and he goes 9 mph more than he did monday and it took him 7 minutes less. how far does he travel to work?
I Don't understand how to set up the problem. I tried making a chart that has distance rate and time .
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
EDIT: Small change in first paragraph so explanation is more reliable.
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The question tells us that the distance to work is not known. Let's call d this distance to work number. We partial information about amount of time to reach work.
WHEN__________rate___________time hours_________distance
Monday________(__)___________35/60______________d
Tuesday_______(__)___________28/60______________d
We do not really know the traveling rates on those days either. We only were given a difference in rate between the days, so we could use r, rate used on Monday. Tuesday was used as 9 mph more than Monday:
WHEN__________rate___________time hours_________distance
Monday________(r)______________35/60______________d
Tuesday_______(r+9)___________28/60______________d
Next, we use the basic concept of rate, r*t=d, rate times time equals distance. The distances of each day are equal.
Monday,
Tuesday,
Reaching this equation, whether the time hour fractions reduced or not, is MOST of the solution. SOLVING for r is fairly straightforward algebra skills. Use the value to find distance or .
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