SOLUTION: Two trains leave their respective stations at the same time travelling towards each other. If train A is travelling at 100 kph and train B at 120 kph and the distance between the t
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Question 769637: Two trains leave their respective stations at the same time travelling towards each other. If train A is travelling at 100 kph and train B at 120 kph and the distance between the two stations is 110 km how long will it be before they meet up ? how far had each train travelled ?
sorry i know this is really easy we are working these out with graphs and i dont get it so i was wondering if any one had any alternatives and please show working ! Thanks :D
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the distance in km that the slower train
will travel until they meet
= the distance the faster train will
travel until they meet
Let = the time elapsed until they meet
----------------------------------------
Slower train's equation:
(1)
Faster train's equation:
(2)
--------------------
(2) is the vertical axis and is the horizontal,
you can plot these.
The point (d,t) where the lines cross is when and where
they meet
Here's the plot:
Note that ( d,t ) = ( 0,0 ) is the starting point for one train
and ( 0,110) is where the other train starts
They meet at ( .5,50 )
Note that 50 km is measured from the slower train's starting point
--------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2) hrs
and
(1)
(1)
(1) km
check:
(2)
(2)
(2) km
----------------
So the slower train travels 50 km
and the faster train travels 110 - d = 60 km
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