Let us say the distance to work is x miles. Case 1: Time taken to travel x miles at 60 mph, is x/60 hours Case 2: Time taken to travel x miles at 30 mph, is x/30 hours Now it is given that x/60 is early and x/30 is late compared to the right time to arrive. Also, the amount of "early" time is the same as the amount of "late" time. So, it means that the "right" time is at the midpoint or average of the 2 times. Right time to reach work =So you need to travel for x/40 hours, to cover the distance of x miles and reach work exactly on time. So the average speed to be maintained = You need to travel at mph to reach on time. Hope you got it. Please email me if it's still not clear. :)