SOLUTION: In still water a boat averages 8 mph it takes the same amount of time to travel 22 miles downstream with the same current as 10 miles upstream against the current whats the rate of

Question 761617: In still water a boat averages 8 mph it takes the same amount of time to travel 22 miles downstream with the same current as 10 miles upstream against the current whats the rate of the water current

Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Distance = Rate x Time

Solve the equation for T by dividing both sides by R

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Let C = the rate of the water current.
The downstream rate is then 8mph + C
and the upstream rate is 8mpH - C.
Since T (The time), is the same in both the upstream and downstream equations, you can set the Distance/Rate ratio equal to each other and solve for C

Multiply both sides by (8+C) and (8-C).

Simplify

Multiply through.

Add 22C to both sides.

Subtract 80 from both sides.

Divide both sides by 32.

The current of the water is 3mph

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