SOLUTION: A truck heads north at a constant speed of 80 km/h. A car leaves 20 minutes later heading north along the same road and travelling at a constant speed of 90 km/h. Write an

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Question 759942: A truck heads north at a constant speed of 80 km/h. A car leaves 20 minutes
later heading north along the same road and travelling at a constant speed of
90 km/h.

Write an equation that could be used to determine how much time in
hours, t, the car travels until it catches up to the truck.
**The correct answer is 90t = 80(t+1/3) , but I need help understanding why**

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
The truck travels for 1/3 hour plus some unknown time, t.
Twenty minutes is 1/3 hour.
This distance is kilometers.

The car, starting from the same departure point, travels for time, t, and catches-up with the truck.
This distance is kilometers.

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

A truck heads north at a constant speed of 80 km/h. A car leaves 20 minutes
later heading north along the same road and travelling at a constant speed of
90 km/h.

Write an equation that could be used to determine how much time in
hours, t, the car travels until it catches up to the truck.
**The correct answer is 90t = 80(t+1/3) , but I need help understanding why**

Let time it takes car to catch up to truck (get to meeting point) be T

Then time it'll take truck to get to meeting point = T + 1/3, since the truck will take a longer time to get to the meeting point as it's traveling at a slower speed

Distance car travels to get to meeting point = 90(T), or 90T

Distance truck travels to get to meeting point = 80(T + 1/3)

Both vehicles would've traveled the same distance, so:

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