SOLUTION: One morning, John drove 11 hours before stopping to eat. After lunch, he increased his speed by 10 mph. If he completed a 590-mile trip in 14 hours of driving time, how fast did he

Question 756905: One morning, John drove 11 hours before stopping to eat. After lunch, he increased his speed by 10 mph. If he completed a 590-mile trip in 14 hours of driving time, how fast did he drive in the morning?

Answer by Nihal@SriLanka(22) (Show Source): You can put this solution on YOUR website!
Assuming morning drive speed was x mph John has driven 11 hrs at speed x and 3 hours at speed (x+10).
Hence forming equation for total distance driven, we have
x.11 + (x+10).3 = 590
i.e. 11x +3x +30= 590
i.e. 14x +30 -30= 590 -30
i.e. 14x = 560
i.e. x = 560/14 = 40 mph
RELATED QUESTIONS
One morning, John drove 5 hours before stopping to eat. After lunch, he increased his... (answered by josmiceli)

One morning, John drove 5 hours before stopping to eat. After lunch he increased his... (answered by rajagopalan)

One morning, John drove 5 hours before stoping to eat. After lunch, he increased his... (answered by ankor@dixie-net.com)

One morning, Justin drove 5 hours before stopping to eat lunch at Chick-fil-A. After... (answered by ikleyn)

One morning, Justin drove 2 hours before stopping to eat lunch at Chick-fil-A. After... (answered by ikleyn)

One morning, Justin drove 3 hours before stopping to eat lunch at Chick-fil-A. After... (answered by Boreal)

One morning, Justin drove 3 hours before stopping to eat lunch at Chick-fil-A. After... (answered by ikleyn,ewatrrr,MathTherapy)

One morning, Justin drove 2 hours before stopping to eat lunch at Pizza Hut. After lunch, (answered by nshah11)

One morning, Justin drove 3 hours before stopping to eat lunch at Pizza Hut. After lunch, (answered by Menjax)