SOLUTION: THE HEIGHT OF THE ROCKET AFTER t SECONDS WHEN FIRED STRAIGHT UP WITH AN INITIAL SPEED OF 150FT PER SECOND FROM AN INITIAL HEIGHT OF 2 CAN BE MODELED BY THE FUNCTION: s(t)=-16t^2+1
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Question 745513: THE HEIGHT OF THE ROCKET AFTER t SECONDS WHEN FIRED STRAIGHT UP WITH AN INITIAL SPEED OF 150FT PER SECOND FROM AN INITIAL HEIGHT OF 2 CAN BE MODELED BY THE FUNCTION: s(t)=-16t^2+150t+2
WHEN WILL THE ROCKET BE 300ft?
WHAT IS THE MEANING OF THE Y INTERCEPT
WHEN WILL IT REACH THE GROUND?
I AM UNSURE OF HOW TO START THE PROBLEM. DO I USE THE QUADRATIC FORMULA?
Found 3 solutions by josmiceli, rothauserc, Alan3354:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
is the height of the rocket from the ground
If you want the height to be ft, then
Divide through by
Use quadratic wquation
sec
In 2.858 sec the height of the rocket will be 300 ft
------------------
I have to run now- check my math. The method
should be OK
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Indeed we use the given equation
s(t)=-16t^2+150t+2
a) when will rocket reach 300 ft
300 = -16t^2 + 150t + 2
-16t^2 + 150t - 298 = 0
use quadratic formula to solve
t = -150 plus or minus sqrt(150^2 - 4(-16)-298) / (-16*2)
b) note if t = 0 then s = 2 which is the initial distance
c) when will it reach the ground
to answer this we use the first derivative which is
-32t+150 and
t <75/16
so the rocket has a maximum height at (75/16, s(75/16))
now we want to know when it will reach the ground, this is just
2 * 75/16 or 75/8 = 9.38 seconds
a nifty free math calculator program for windows is "speedcrunch" :-)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
THE HEIGHT OF THE ROCKET AFTER t SECONDS WHEN FIRED STRAIGHT UP WITH AN INITIAL SPEED OF 150FT PER SECOND FROM AN INITIAL HEIGHT OF 2 CAN BE MODELED BY THE FUNCTION: s(t)=-16t^2+150t+2
===========================
This is not a rocket, it's a projectile.
Rockets have engines and thrust.
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