SOLUTION: Susan leaves home at 8am, driving to a friend's cabin. Her sister, Carol, leaves home an hour later also driving to the cabin. By driving 7 mph faster than Susan, Carol overtakes S
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Question 741511: Susan leaves home at 8am, driving to a friend's cabin. Her sister, Carol, leaves home an hour later also driving to the cabin. By driving 7 mph faster than Susan, Carol overtakes Susan at 2pm.
What was the average speed of each sister?
How far do they drive before Carol overtakes Susan?
Please show work, if you have to.
Thank you
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
From 8 am to 2 pm is 6 hours, so Susan drove at 
miles per hour for 6 hours and therefore travelled 
miles. Carol only drove for 5 hours, because she left one hour later. But she travelled at 
miles per hour, so she travelled 
miles. Those two distances have to be equal, so set them equal and solve for . Once you know , Susan's speed, you can add 7 to get Carol's speed. Calculate to get the distance traveled. Then calculate )
to check your work.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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