SOLUTION: a man had a a bag of sweets.he gave to his son one sweet and 1/7 of the remainning sweets.from what was left he gave to his daughter two sweets and 1/7 of the remainnig sweets.the

Question 739840: a man had a a bag of sweets.he gave to his son one sweet and 1/7 of the remainning sweets.from what was left he gave to his daughter two sweets and 1/7 of the remainnig sweets.the two children found that they had the same numbers of sweets how many sweets were there in the orignal bag?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
N = Original number of sweets in the bag.

Son: received.

Number of sweets remaining in bag is . The variable R is assigned as the number of sweets now REMAINING in the bag after the son received his allotment of sweets.

Daughter: which is substituting for R,

=2+N/7-1/7-N/(7^2)
= received.

Each child has the same number of sweets:

Multiply left and right members by ,

Forty-Two sweets originally in the bag.
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