SOLUTION: [Randy drove from his house to Dallad at an average speed of 50 mph. On the return trip, he drove at an average speed of 55 mph. The return trip took randy 1 hour less than the tri

Question 737331: [Randy drove from his house to Dallad at an average speed of 50 mph. On the return trip, he drove at an average speed of 55 mph. The return trip took randy 1 hour less than the trip to Dallas. How many hours did he drive in all?] I want to know how to solve these kinds of word problems, can someone please start with this?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Fundamentally, {rate}*{time}={distance}.

Make a data table to relate the categories of movement and the measures.
Letting h = time in hours for the trip TO Dallas,

Where to___________rate___________time____________distance
Going______________50_____________h_______________(___)
Returning__________55_____________h-1_____________(___)

Some information is missing and must be filled. We can find expressions for the missing distances. We have rates, and we have times, although not all fully known; and we can make expressions therefore for distances.

Where to___________rate___________time____________distance
Going______________50_____________h_______________( )
Returning__________55_____________h-1_____________( )

We do not care about any totals. Should we understand that the distance going to Dallas and the distance from Dallas back to the starting point are the same value? ABSOLUTELY the distance going and the distance returning are equal. We must do something with that.
...
Do you need the last bit (or couple bits) of help?

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