SOLUTION: A van departs from a rest stop at 9am heading west and travels at an average rate of 40 miles per hour. two hours later a car departs from the same rest stop also heading west and

Question 736425: A van departs from a rest stop at 9am heading west and travels at an average rate of 40 miles per hour. two hours later a car departs from the same rest stop also heading west and travels at an average rate of 65 miles per hour. at what time will the car catch up to the van and how far will they have traveled at that time?
I need to build an equation, and so far all i have is this;
Rate x Time = Dist
40 x 40x
40-x 2 2(40-x)
this just feels all wrong... 40x + 65(2+x) =

9
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
First car 40 mph
Car II 65 mph
First car 09:00
Car II 11:00
Difference in time= 02:00 => 2.00 hours
First car will have covered 80.00 miles Car II starts
catch up distance= 80.00 miles
catch up speed = 65 -40
catch up speed = 25 mph
Catchup time = catchup distance/catch up speed
catch up time= 3.2
catch up time= 3.20 hours
They will meet at 12:20 pm
Car II speed = 65 hours
Time to catch up = 3.2
D=Speed * time
D= 65 * 3.2
D= 208 miles
Car II will catch up when it has traveled 208 miles

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