SOLUTION: A helicopter leaves an airport and flies south at 180 mi/h. Thirty minutes later, an airplane leaves the airport and follows the same route as the helicopter, only at a higher elev
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Question 734513: A helicopter leaves an airport and flies south at 180 mi/h. Thirty minutes later, an airplane leaves the airport and follows the same route as the helicopter, only at a higher elevation. The airplane is flying 330 mi/h. How many minutes will it take for the airplane to catch up with the helicopter?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
D=RT
D=180T FOR THE HELICOPTER.
D=330(T-.5) FOR THE PLANE.
180T=330(T-.5)
180T=330T-165
330T-180T=165
150T=165
T=165/150
T=1.1 HOURS (66 min.) AFTER THE HELICOPTER LEAVES THEY WILL MEET.
PROOF:
180*1.1=330(1.1-.5)
198=330*.6
198=198
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