SOLUTION: A train leaves a station at 9.00 p.m. Another train leaves same station at 10.00 p.m. first train runs at 35 kmph and Second train crosses the first train in 4 hours.

Question 734095: A train leaves a station at 9.00 p.m. Another train leaves same station at 10.00 p.m. first train runs at 35 kmph and Second train crosses the first train in 4 hours. Find the speed of the second train.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
difference of time between Train I and Train II 1 hour
speed of train I = 35 kmph
speed of train II = x kmph
catch up speed = x-35
catch up time = 4 hours
catch up distance = 35 km ( distance traveled in 1 hour by Train I)

t= d/s
4 = 35/(x-35)
4(x-35)=35
4x-140=35
4x=140+35
4x=175
x= 43.75 kmph
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