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a boatman goes 96 km in 8 hours with the flow of a river and returns in 12 hours (against the flow).
what will be the respective speed of the boat and the river (in km/hour)?
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Let u be the speed of the boat at no current (in kilometers per hour),
and let v be the rate of the current.
The speed of the boat with the current is 96/8 = 12 km/h.
The speed of the boat against the current is 96/12 = 8 km/h.
The speed of the boat with the current is (u + v) km/h.
The speed of the boat against the current is (u - v) km/h.
So, we have these equations
u + v = 12, (1)
u - v = 8. (2)
By adding equations (1) and (2), we get 2u = 12 + 8 = 20; hence, u = 20/2 = 10 km/h.
By subtracting equation (2) from equation (1), we get 2v = 12 - 8 = 4; hence, v = 4/2 = 2 km/h.
ANSWER. The speed of the boat at no current is 10km/h.
The rate of the current is 2 km/h.
Solved.
The answers in the post by @lynnlo are incorrect.