SOLUTION: A cyclist and a jogger start in a town and want to end 12 miles away. The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclis

Question 733600: A cyclist and a jogger start in a town and want to end 12 miles away. The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclist.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A cyclist and a jogger start in a town and want to end 12 miles away.
The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclist.
:
let r = rate of the jogger
then
2r = rate of the cyclist
:
Write a time equation: time = dist/rate
:
jogger time - cyclist time = 1.2 hr
- = 1.2
reduce the fraction
- = 1.2
multiply by r
12 - 6 = 1.2r
6 = 1.2r
r = 6/1.2
r = 5 mph rate of the jogger
then
2(5) = 10 mph rate of the cyclist
:
:
check this; find the actual time of each
12/5 = 2.4 hrs
12/10= 1.2 hrs
---------------
differ: 1.2 hrs
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