You can
put this solution on YOUR website!Distance(d)=rate(r) times time(t) or d=rt
Clearly, the planes are separating at the rate of 220 mph plus 195 mph or
415 mi/hr. Also 20 min =1/3 hr----So:
d=rt
d=415 mi/hr(1/3 hr)
d=138.333 mi
Another approach would be to determine how far each plane traveled in 20 min and then add the two distances together:.e.g.,
195/3+220/3=
65+73.333=138.333 mi
Hope this helps----ptaylor