SOLUTION: Two cyclists 65 miles apart start biking toward each other at the same time. One cyclist bikes 5 miles per hour faster than the other; assume they travel at constant speeds. If the
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Question 731585: Two cyclists 65 miles apart start biking toward each other at the same time. One cyclist bikes 5 miles per hour faster than the other; assume they travel at constant speeds. If they meet 2 hours later, how fast is the faster cyclist traveling?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You can think of this as one cyclist standing still and
the other one approaching at the sum of their speeds
Let = the speed of the slower cyclist in mi/hr
= the speed of the faster cyclist in mi/hr
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The faster cyclist's speed is 18.75 mi/hr
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check:
Faster cyclist:
Slower cyclist:
--------------
OK
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