SOLUTION: system of equations 2 cars start from points 92 miles apart and travel directly towards each other. one car starts at 11am and travels slower and the other starts at 11:15am and g

Question 730190: system of equations
2 cars start from points 92 miles apart and travel directly towards each other. one car starts at 11am and travels slower and the other starts at 11:15am and goes faster to make up for lost time. they meet at 12pm find the average speed of each car, if the slower car travels 6 mph slower than the faster one.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the speed of slower car be x
the speed of car II = x+6
They meet after 1 hour after car I starts
distance by car I = x
distance by car II = (x+6)*3/4........... ( speed * time)
x+3/4(x+6)=92
multiply by 4
4x+3(x+6)=368
4x+3x+18=350
7x=350
x=50
50 & 56mph
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