SOLUTION: car A left dagupan at 9:00 am going to manila with a velocity of 40km/hr. after 1hr,car B left from the same location and taken the same route as car A going to manila. if car B

Question 729600: car A left dagupan at 9:00 am going to manila with a velocity of 40km/hr.
after 1hr,car B left from the same location and taken the same route as car A going to manila. if car B has a velocity of 90km/hr, what time does car B over take car A?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
First car 40 mph
Car II 90 mph
First car 09:00
Car II 10:00
Difference in time= 01:00 => 1.00 hours
First car will have covered 40.00 miles Car II starts
catch up distance= 40.00 miles
catch up speed = 90 -40
catch up speed = 50 mph
Catchup time = catchup distance/catch up speed
catch up time= 0.8
catch up time= 0.80 hours =48 minutes
They will meet at 10:48 pm

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