SOLUTION: Running a race, Roger can run one mile in 8 minutes. Jeff can run one mile in 6 minutes. If Jeff gives Roger a 1 minute start, how long will it take before jeff catches up to Roger

Question 728823: Running a race, Roger can run one mile in 8 minutes. Jeff can run one mile in 6 minutes. If Jeff gives Roger a 1 minute start, how long will it take before jeff catches up to Roger? How far will each have run?
Found 2 solutions by solver91311, josgarithmetic:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

If the first guy runs 1 mile in 8 minutes, then he runs 1/8 mile in one minute. Likewise, the other guy runs 1/6 mile in one minute.

In minutes the first guy will run miles. In one less minute, i.e. minutes, the second guy will run miles. You just need to find the value of that makes

And then calculate either or . Hint: Cross-multiply and then solve the linear equation for

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Key here is that Roger has already ran for 1 minute at 1/8 miles per minute. He has gone 1/8 of a mile. May be easier to think of the route as a position path. When will Roger and Jeff reach the same position? TIME is the variable to solve for. You'd use expressions of distance but you're not really looking for distance.

Is that enough for you to make progress with this exercise?
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