SOLUTION: A JOGGER STARTS FROM ONE END OF A 15 MILE NATURE TRAIL AT 8:00 AM ONE HOUR LATER A CYCLIST STARTS FROM THE OTHER END OF THE TRAIL AND RIDES TOWARD THE JOGGER IF THE RATE OF THE JOG
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Question 720607: A JOGGER STARTS FROM ONE END OF A 15 MILE NATURE TRAIL AT 8:00 AM ONE HOUR LATER A CYCLIST STARTS FROM THE OTHER END OF THE TRAIL AND RIDES TOWARD THE JOGGER IF THE RATE OF THE JOGGER IS 6MPH AND THE RATE OF THE CYCLIST IS 9MPH AT WHAT TIME WILL THE TWO MEET?
THANK YOU
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You can think of the jogger as standing still and
the cyclist approaching at the sum of their speeds
-----------
The jogger cuts down the distance between them by
mi
So now the cyclist only has to travel mi
-----------
Let = the time in hrs it takes the cyclist to meet the jogger
hrs
min
The two will meet at 8:36 AM
-----------
check:
jogger's equation:
mi
Cyclist's equation:
must = 9 mi
OK
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