SOLUTION: 23. A cross-country skier leaves a camp to explore a wilderness area. Two hours later a friend leaves the camp in a snowmobile, travelling 4 mph faster than the skier, and meets th
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Question 71724This question is from textbook Algebra: Introductory and Intermediate
: 23. A cross-country skier leaves a camp to explore a wilderness area. Two hours later a friend leaves the camp in a snowmobile, travelling 4 mph faster than the skier, and meets the skier 1 h later. Find the rate of the snowmobile.
This question is from textbook Algebra: Introductory and Intermediate
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A cross-country skier leaves a camp to explore a wilderness area. Two hours later a friend leaves the camp in a snowmobile, traveling 4 mph faster than the skier, and meets the skier 1 h later. Find the rate of the snowmobile.
:
Let s = speed of the snowmobile:
Let (s-4) = speed of the skier
:
We know that when the snowmobile overtakes the skier, they will have traveled the same distance.
Make an equation from that fact; d = time * speed
:
Traveling time for the skier: 3 hrs
Travel time for the snmob: 1 hr
:
skier dist = snmbl dist
3(s-4) = 1s
3s -12 = s
3s - s = +12
2s = 12
s = 12/2
s = 6 mph is the speed of the snmob
:
:
Check using distance equality
1*6 = 3*2
:
:
Pretty simple, right?
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