SOLUTION: A rock is thrown upward from the edge of a cliff. The rock follows the equation below: S=24+64t-16t^2 What is the greatest height above the ground that this rock will go?

Question 716627: A rock is thrown upward from the edge of a cliff. The rock follows the equation below:
S=24+64t-16t^2
What is the greatest height above the ground that this rock will go?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A rock is thrown upward from the edge of a cliff. The rock follows the equation below:
S=24+64t-16t^2
What is the greatest height above the ground that this rock will go?
---------------
Max height is at the vertex of the parabola.
Vertex is on the AOS, Axis of Symmetry, t = -b/2a = -64/-32
@ t = 2, S = 24 + 128 - 64
S = 88 ft

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