SOLUTION: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Fin
Algebra.Com
Question 709392: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Find the distance of the run.
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
pp
The Joggers__________rate__________time hrs.___________distance
fast_________________7_____________t___________________d
slower_______________4_____________t+2/3_______________d
The (2/3) of the hour is the same as 40 minutes.
The distance that each jogged is the same, so equate the expressions for their distance, rate in miles per hour multiplied by the hours.
, and solve for t in hours. Once t is known, use either joggers data to compute d.
, hours
, miles
(This result appeared to be about a 10 kilometer event.)
RELATED QUESTIONS
Two Joggers, one averaging 9 mph and one averaging 5 mph, start from a designated initial (answered by ankor@dixie-net.com)
Two joggers, one averaging 6 mph and one averaging 5 mph, start from a designated initial (answered by sofiyac)
Two joggers, one averaging 7 mph and one averaging 4 mph, start from a designated initial (answered by richwmiller)
Two joggers, one averaging 5
mph and one averaging 4
mph, start... (answered by josgarithmetic,ikleyn)
2 joggers, 1 averaging 9 mph and 1 averaging 6 mph, start from a designated initial... (answered by josgarithmetic)
This is from a worksheet given by my professor, not from a textbook.
Two bicyclists,... (answered by ankor@dixie-net.com)
at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running (answered by mananth,josmiceli)
Two joggers start at the same time from opposite end of an 8-mile jogging trail and begin (answered by nerdybill)
Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour,... (answered by josgarithmetic)