SOLUTION: For the hockey tournament, two buses leave 20 minutes apart and travel along the same road. The first bus travels at 66km/h and the later bus, 77km/h. How long will it take befor

Question 701005:
For the hockey tournament, two buses leave 20 minutes apart and travel along the same road. The first bus travels at 66km/h and the later bus, 77km/h. How long will it take before the later bus catches up?
(I know the answer : 2 hours, but I don't know how to show my work. I know it involves something like how much the first bus travelled before the later bus. { 11km })
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
D=RT
D=66T FOR THE FIRST BUS.
D=77(T-20/60) OR
D=77(T-.33) FOR THE SECOND BUS.
SINCE THE 2 DISTANCES ARE EQUAL THUS:
66T=77(T-.33)
66T=77T-25.41
66T-77T=-25.41
-11T=-25.41
T=-25.41/-11
T=2.31 HOURS.
PROOF:
66*2.31=77(2.31-.33)
152.46=77*1.98
152.46=152.46
#########################################
IF THE ANSWER IS 2 HOURS THEN:
66*2=77(2-20/60)
132=77(2-.33)
132=77*1.67
132=128.33 DOES NOT COMPUTE.

RELATED QUESTIONS
Two buses leave a station at the same time and travel in opposite directions. One bus... (answered by Alan3354)

Two buses leave a station at the same time and travel in opposite directions. One bus... (answered by rfer)

Two buses leave a station at the same time and travel in opposite directions. One bus... (answered by mananth)

Two buses leave a station at the same time and travel in opposite directions. One bus... (answered by josgarithmetic)

Two buses leave a station at the same time and travel in opposite directions. One bus... (answered by ikleyn)

two buses leave the same station at 7:00 pm. One bus travel north at the rate of kph and... (answered by rfer)

Two buses leave Chicago at the same time in opposite directions. One travels at an... (answered by jorel555)