SOLUTION: A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate
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Question 698323: A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind?
**
let x=rate of jet in still air
let c=rate of wind
x+c=rate downwind
x-c=rate against wind
**
Distance/travel time=rate
5400/6=x-c
5400/5=x+c
..
900=x-c
1080=x+c
add
1980=2x
x=990
c=x-900
c=90
rate of jet in still air=990 mph
rate of wind=90 mph
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