SOLUTION: what does this problem mean. A car leaves a city at the rate of 60 mi/h and goes 80 miles before a second car follows at a rate of 70 mi/h. How long will it take for the second car

Question 697658: what does this problem mean. A car leaves a city at the rate of 60 mi/h and goes 80 miles before a second car follows at a rate of 70 mi/h. How long will it take for the second car to overtake the first?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A car leaves a city at the rate of 60 mi/h and goes 80 miles before a second car follows at a rate of 70 mi/h.
How long will it take for the second car to overtake the first?
:
Let t = travel time of the 2nd car when it overtakes the 1st
:
Find the travel time of the 1st car to go 80 mi; time = dist/speed
time =
time = 1.33 hrs for the 1st car to go 80 mi
therefore
(t+1.33) = travel time of the 1st car when it is overtaken
:
When the 2nd overtakes the 1st, they will have traveled the same distance
Write a distance equation, dist = speed * time
:
2nd car dist = 1st car dist
70t = 60(t+1.33)
70t = 60t + 80
70t - 60t = 80
10t = 80
t = 8 hrs travel time of the 2nd car to overtake the 1st
:
;
Confirm this by finding the actual distances, should be equal
70*8 = 560 mi
60*9.33 ~ 560 mi

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